What are the solutions to the equation 6x^2+6=12x+18 ?

The solutions to the equation 6x^2+6=12x+18 are x=1+sqrt(3),x=1-sqrt(3)

Find the zeros of 6x^2+6=12x+18

The zeros of 6x^2+6=12x+18 are x=1+sqrt(3),x=1-sqrt(3)

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6 x^{2} + 6 = 12 x + 18

x = 1 + 3, x = 1 - 3

Decimal Notation

x = 2.73205 \dots, x = - 0.73205 \dots

Solution steps

6 x^{2} + 6 = 12 x + 18

Move

18

to the left side

6 x^{2} - 12 = 12 x

Move

12 x

to the left side

6 x^{2} - 12 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 12 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 (- 12) = 123

x_{1, 2} = \frac{- ( - 12 ) \pm 12 3}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 3}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 12 3}{2 \cdot 6}

x = \frac{- ( - 12 ) + 12 3}{2 \cdot 6} : 1 + 3

x = \frac{- ( - 12 ) - 12 3}{2 \cdot 6} : 1 - 3

The solutions to the quadratic equation are:

x = 1 + 3, x = 1 - 3

4 x^{3} - 20 x^{2} + 24 x

2 x + 9 > 11

6 x^{2} - 5 x + 8 = 0

∣ 2 x - 5 ∣ - 8 = 3

What are the solutions to the equation 6x^2+6=12x+18 ?
The solutions to the equation 6x^2+6=12x+18 are x=1+sqrt(3),x=1-sqrt(3)
Find the zeros of 6x^2+6=12x+18
The zeros of 6x^2+6=12x+18 are x=1+sqrt(3),x=1-sqrt(3)