What are the solutions to the equation x^2+1/4 =0 ?

The solutions to the equation x^2+1/4 =0 are x= 1/2 i,x=-1/2 i

Find the zeros of x^2+1/4 =0

The zeros of x^2+1/4 =0 are x= 1/2 i,x=-1/2 i

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x^{2} + \frac{1}{4} = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

x^{2} + \frac{1}{4} = 0

Move

\frac{1}{4}

to the right side

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

\frac{3}{4 ^{- 2}}

- 6 x^{2} + 48 x + 54 = 0

4 a^{2} - 81 b^{2}

\frac{1}{4} \cdot 7

6 x^{2} - 42 x + 60 = 0

What are the solutions to the equation x^2+1/4 =0 ?
The solutions to the equation x^2+1/4 =0 are x= 1/2 i,x=-1/2 i
Find the zeros of x^2+1/4 =0
The zeros of x^2+1/4 =0 are x= 1/2 i,x=-1/2 i