What are the solutions to the equation m^2=2m ?

The solutions to the equation m^2=2m are m=2,m=0

Find the zeros of m^2=2m

The zeros of m^2=2m are m=2,m=0

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m^{2} = 2 m

m = 2, m = 0

Solution steps

m^{2} = 2 m

Move

2 m

to the left side

m^{2} - 2 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

m_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

m = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 2, m = 0

\frac{900}{1.86 \cdot 1 0 ^{- 2}}

\frac{4 p + 3}{8} = \frac{p + 2}{4}

(x + 6) (2 x - 1) = 0

0 = (x - 2)^{2}

∣ x - 3 ∣ < 4

What are the solutions to the equation m^2=2m ?
The solutions to the equation m^2=2m are m=2,m=0
Find the zeros of m^2=2m
The zeros of m^2=2m are m=2,m=0