What are the solutions to the equation (3w-5)w=50 ?

The solutions to the equation (3w-5)w=50 are w=5,w=-10/3

Find the zeros of (3w-5)w=50

The zeros of (3w-5)w=50 are w=5,w=-10/3

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(3 w - 5) w = 50

w = 5, w = - \frac{10}{3}

Solution steps

(3 w - 5) w = 50

Expand

(3 w - 5) w : 3 w^{2} - 5 w

3 w^{2} - 5 w = 50

Move

50

to the left side

3 w^{2} - 5 w - 50 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 50 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 50) = 25

w_{1, 2} = \frac{- ( - 5 ) \pm 25}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 25}{2 \cdot 3}, w_{2} = \frac{- ( - 5 ) - 25}{2 \cdot 3}

w = \frac{- ( - 5 ) + 25}{2 \cdot 3} : 5

w = \frac{- ( - 5 ) - 25}{2 \cdot 3} : - \frac{10}{3}

The solutions to the quadratic equation are:

w = 5, w = - \frac{10}{3}

(2)^{2}

∣ x + 3 ∣ \leq - 8

(x - 5)^{2} = 3

\frac{5}{12} + \frac{3}{4}

\frac{5 ^{3}}{3} - 7 (5)^{2} + 48 (5)

What are the solutions to the equation (3w-5)w=50 ?
The solutions to the equation (3w-5)w=50 are w=5,w=-10/3
Find the zeros of (3w-5)w=50
The zeros of (3w-5)w=50 are w=5,w=-10/3