What are the solutions to the equation 7x^2+6x+2=0 ?

The solutions to the equation 7x^2+6x+2=0 are x=-3/7+i(sqrt(5))/7 ,x=-3/7-i(sqrt(5))/7

Find the zeros of 7x^2+6x+2=0

The zeros of 7x^2+6x+2=0 are x=-3/7+i(sqrt(5))/7 ,x=-3/7-i(sqrt(5))/7

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7 x^{2} + 6 x + 2 = 0

x = - \frac{3}{7} + i \frac{5}{7}, x = - \frac{3}{7} - i \frac{5}{7}

Solution steps

7 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

Simplify

6^{2} - 4 \cdot 7 \cdot 2 : 25 i

x_{1, 2} = \frac{- 6 \pm 2 5 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 6 + 2 5 i}{2 \cdot 7}, x_{2} = \frac{- 6 - 2 5 i}{2 \cdot 7}

x = \frac{- 6 + 2 5 i}{2 \cdot 7} : - \frac{3}{7} + i \frac{5}{7}

x = \frac{- 6 - 2 5 i}{2 \cdot 7} : - \frac{3}{7} - i \frac{5}{7}

The solutions to the quadratic equation are:

x = - \frac{3}{7} + i \frac{5}{7}, x = - \frac{3}{7} - i \frac{5}{7}

- 0.04

7 x^{2} + 2 x - 5

(5 x - 2)^{2} \leq 0

4 (2 x - 9) = 4

3 (- 2)

What are the solutions to the equation 7x^2+6x+2=0 ?
The solutions to the equation 7x^2+6x+2=0 are x=-3/7+i(sqrt(5))/7 ,x=-3/7-i(sqrt(5))/7
Find the zeros of 7x^2+6x+2=0
The zeros of 7x^2+6x+2=0 are x=-3/7+i(sqrt(5))/7 ,x=-3/7-i(sqrt(5))/7