What are the solutions to the equation 3x^2-6=-3x ?

The solutions to the equation 3x^2-6=-3x are x=1,x=-2

Find the zeros of 3x^2-6=-3x

The zeros of 3x^2-6=-3x are x=1,x=-2

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3 x^{2} - 6 = - 3 x

x = 1, x = - 2

Solution steps

3 x^{2} - 6 = - 3 x

Move

3 x

to the left side

3 x^{2} - 6 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 6) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 3}, x_{2} = \frac{- 3 - 9}{2 \cdot 3}

x = \frac{- 3 + 9}{2 \cdot 3} : 1

x = \frac{- 3 - 9}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

x^{2} = 0

(a - 2 b) (x - 2 y) + (2 b - a) (x - y)

\frac{( 3 x - 2 )}{5} = 2 x - 3

15 n^{3} + 25 n^{2}

(1 + \frac{0.11}{12})^{12} - 1

What are the solutions to the equation 3x^2-6=-3x ?
The solutions to the equation 3x^2-6=-3x are x=1,x=-2
Find the zeros of 3x^2-6=-3x
The zeros of 3x^2-6=-3x are x=1,x=-2