What are the solutions to the equation x^2-6x=5x-18 ?

The solutions to the equation x^2-6x=5x-18 are x=9,x=2

Find the zeros of x^2-6x=5x-18

The zeros of x^2-6x=5x-18 are x=9,x=2

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x^{2} - 6 x = 5 x - 18

x = 9, x = 2

Solution steps

x^{2} - 6 x = 5 x - 18

Move

18

to the left side

x^{2} - 6 x + 18 = 5 x

Move

5 x

to the left side

x^{2} - 11 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 18 = 7

x_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 1}

x = \frac{- ( - 11 ) + 7}{2 \cdot 1} : 9

x = \frac{- ( - 11 ) - 7}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 9, x = 2

(25 + 7)^{2}

lo g_{\frac{1}{5}} (125)

x^{2} = - 24

\frac{6 ^{2} u ^{3} v ^{- 3}}{12 u ^{- 2} v}

\frac{1}{4} (12) + 1

What are the solutions to the equation x^2-6x=5x-18 ?
The solutions to the equation x^2-6x=5x-18 are x=9,x=2
Find the zeros of x^2-6x=5x-18
The zeros of x^2-6x=5x-18 are x=9,x=2