What are the solutions to the equation 5x^2-7x-6=-10x-4 ?

The solutions to the equation 5x^2-7x-6=-10x-4 are x= 2/5 ,x=-1

Find the zeros of 5x^2-7x-6=-10x-4

The zeros of 5x^2-7x-6=-10x-4 are x= 2/5 ,x=-1

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5 x^{2} - 7 x - 6 = - 10 x - 4

x = \frac{2}{5}, x = - 1

Solution steps

5 x^{2} - 7 x - 6 = - 10 x - 4

Move

4

to the left side

5 x^{2} - 7 x - 2 = - 10 x

Move

10 x

to the left side

5 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 2) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 5}, x_{2} = \frac{- 3 - 7}{2 \cdot 5}

x = \frac{- 3 + 7}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 3 - 7}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 1

5 v^{2} - 45 = 0

5 - 9 c < - 13

\frac{x}{3} - \frac{1}{6} \leq \frac{x}{4} + 1

3 m^{2} + 7 m - 6

(x^{2} + 1)^{2} > 0

What are the solutions to the equation 5x^2-7x-6=-10x-4 ?
The solutions to the equation 5x^2-7x-6=-10x-4 are x= 2/5 ,x=-1
Find the zeros of 5x^2-7x-6=-10x-4
The zeros of 5x^2-7x-6=-10x-4 are x= 2/5 ,x=-1