What is the answer to (6x+1}{11}=\frac{2x-3)/7 ?

The answer to (6x+1}{11}=\frac{2x-3)/7 is x=-2

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(6x+1}{11}=\frac{2x-3)/7

\frac{6 x + 1}{11} = \frac{2 x - 3}{7}

x = - 2

Solution steps

\frac{6 x + 1}{11} = \frac{2 x - 3}{7}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(6 x + 1) \cdot 7 = 11 (2 x - 3)

Expand

(6 x + 1) \cdot 7 : 42 x + 7

Expand

11 (2 x - 3) : 22 x - 33

42 x + 7 = 22 x - 33

Move

7

to the right side

42 x = 22 x - 40

Move

22 x

to the left side

20 x = - 40

Divide both sides by

20

x = - 2

4 x^{2} + 26 x + 30

x^{3} - 5 x^{2} + 3 x + 9

(8 d)^{\frac{2}{3}}

- 6 \geq 4 - 5 x^{3}

- 338 = 7 (4 + 8 b) + 5 b

What is the answer to (6x+1}{11}=\frac{2x-3)/7 ?
The answer to (6x+1}{11}=\frac{2x-3)/7 is x=-2
Solve for x: (6x+1}{11}=\frac{2x-3)/7
The solution is x=-2