What are the solutions to the equation x^2+6x-60=3x-20 ?

The solutions to the equation x^2+6x-60=3x-20 are x=5,x=-8

Find the zeros of x^2+6x-60=3x-20

The zeros of x^2+6x-60=3x-20 are x=5,x=-8

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x^{2} + 6 x - 60 = 3 x - 20

x = 5, x = - 8

Solution steps

x^{2} + 6 x - 60 = 3 x - 20

Move

20

to the left side

x^{2} + 6 x - 40 = 3 x

Move

3 x

to the left side

x^{2} + 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 40) = 13

x_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 13}{2 \cdot 1}, x_{2} = \frac{- 3 - 13}{2 \cdot 1}

x = \frac{- 3 + 13}{2 \cdot 1} : 5

x = \frac{- 3 - 13}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 5, x = - 8

2 7^{- \frac{2}{3}}

x^{2} \cdot y^{2}

∣ 3 x - 4 ∣ < 5

- 1 + 9

5 ∣ d + 8 ∣ - 7 \geq 13

What are the solutions to the equation x^2+6x-60=3x-20 ?
The solutions to the equation x^2+6x-60=3x-20 are x=5,x=-8
Find the zeros of x^2+6x-60=3x-20
The zeros of x^2+6x-60=3x-20 are x=5,x=-8