What are the solutions to the equation 5v^2-15v+12=3v ?

The solutions to the equation 5v^2-15v+12=3v are v=(9+sqrt(21))/5 ,v=(9-sqrt(21))/5

Find the zeros of 5v^2-15v+12=3v

The zeros of 5v^2-15v+12=3v are v=(9+sqrt(21))/5 ,v=(9-sqrt(21))/5

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5 v^{2} - 15 v + 12 = 3 v

v = \frac{9 + 21}{5}, v = \frac{9 - 21}{5}

Solution steps

5 v^{2} - 15 v + 12 = 3 v

Move

3 v

to the left side

5 v^{2} - 18 v + 12 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

(- 18)^{2} - 4 \cdot 5 \cdot 12 = 221

v_{1, 2} = \frac{- ( - 18 ) \pm 2 21}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 18 ) + 2 21}{2 \cdot 5}, v_{2} = \frac{- ( - 18 ) - 2 21}{2 \cdot 5}

v = \frac{- ( - 18 ) + 2 21}{2 \cdot 5} : \frac{9 + 21}{5}

v = \frac{- ( - 18 ) - 2 21}{2 \cdot 5} : \frac{9 - 21}{5}

The solutions to the quadratic equation are:

v = \frac{9 + 21}{5}, v = \frac{9 - 21}{5}

30 > x + 10 > 20

3 y^{2} + 21 y + 36

x^{4} + 3 x^{3} - 7 x^{2} - 27 x - 18 \leq 0

m^{2} + 12 m - 13

- 6 x + 5 > - 1

What are the solutions to the equation 5v^2-15v+12=3v ?
The solutions to the equation 5v^2-15v+12=3v are v=(9+sqrt(21))/5 ,v=(9-sqrt(21))/5
Find the zeros of 5v^2-15v+12=3v
The zeros of 5v^2-15v+12=3v are v=(9+sqrt(21))/5 ,v=(9-sqrt(21))/5