What are the solutions to the equation 3(x+10)^2+13=40 ?

The solutions to the equation 3(x+10)^2+13=40 are x=-7,x=-13

Find the zeros of 3(x+10)^2+13=40

The zeros of 3(x+10)^2+13=40 are x=-7,x=-13

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3 (x + 10)^{2} + 13 = 40

x = - 7, x = - 13

Solution steps

3 (x + 10)^{2} + 13 = 40

Move

13

to the right side

3 (x + 10)^{2} = 27

Divide both sides by

3

(x + 10)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 10 = 9 : x = - 7

Solve

x + 10 = - 9 : x = - 13

The solutions to the quadratic equation are:

x = - 7, x = - 13

\frac{1}{5} (x - 6) = 3 x - 2 (x - 1) + \frac{24}{5}

N a O H + H Cl

- 10 > - 8 + y

\frac{2}{2}

2 x y - 9 x

What are the solutions to the equation 3(x+10)^2+13=40 ?
The solutions to the equation 3(x+10)^2+13=40 are x=-7,x=-13
Find the zeros of 3(x+10)^2+13=40
The zeros of 3(x+10)^2+13=40 are x=-7,x=-13