What is ((7-8i))/((4-5i)) ?

The solution to ((7-8i))/((4-5i)) is 68/41+3/41 i

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simplify ((7-8i))/((4-5i))

simplify

\frac{( 7 - 8 i )}{( 4 - 5 i )}

\frac{68}{41} + \frac{3}{41} i

Solution steps

\frac{7 - 8 i}{4 - 5 i}

Multiply by the conjugate

\frac{4 + 5 i}{4 + 5 i}

= \frac{( 7 - 8 i ) ( 4 + 5 i )}{( 4 - 5 i ) ( 4 + 5 i )}

Simplify

\frac{( 7 - 8 i ) ( 4 + 5 i )}{( 4 - 5 i ) ( 4 + 5 i )} : \frac{68 + 3 i}{41}

= \frac{68 + 3 i}{41}

Rewrite in standard complex form:

\frac{68}{41} + \frac{3}{41} i

= \frac{68}{41} + \frac{3}{41} i

\frac{x + 3}{( x - 4 ) ^{2} ( x ^{2} - 4 )} \leq 0

9 (x + 5) \leq 7 (x + 1) + 45

9 x + 5 > - 6

e^{x} \cdot e^{2 x}