What is 1/x+1/(x+1)>= 2/(x+2) ?

The solution to 1/x+1/(x+1)>= 2/(x+2) is x 0

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1/x+1/(x+1)>= 2/(x+2)

\frac{1}{x} + \frac{1}{x + 1} \geq \frac{2}{x + 2}

x < - 2 or - 1 < x \leq - \frac{2}{3} or x > 0

Interval Notation

(- \infty, - 2) \cup (- 1, - \frac{2}{3}] \cup (0, \infty)

Decimal Notation

x < - 2 or - 1 < x \leq - 0.66666 \dots or x > 0

Solution steps

\frac{1}{x} + \frac{1}{x + 1} \geq \frac{2}{x + 2}

Rewrite in standard form

\frac{3 x + 2}{x ( x + 1 ) ( x + 2 )} \geq 0

Identify the intervals

x < - 2 or - 1 < x \leq - \frac{2}{3} or x > 0

\frac{1}{x + 5} > - 2

3 w + 2 w = 20

6 = - \frac{3}{2} x + 3

2 v m^{2} - 14 v m

- x^{3} + 3 x + 2

What is 1/x+1/(x+1)>= 2/(x+2) ?
The solution to 1/x+1/(x+1)>= 2/(x+2) is x<-2\lor-1<x<=-2/3 \lor x>0