What are the solutions to the equation m^2+5=0 ?

The solutions to the equation m^2+5=0 are m=sqrt(5)i,m=-sqrt(5)i

Find the zeros of m^2+5=0

The zeros of m^2+5=0 are m=sqrt(5)i,m=-sqrt(5)i

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m^{2} + 5 = 0

m = 5 i, m = - 5 i

Solution steps

m^{2} + 5 = 0

Move

5

to the right side

m^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 5, m = - - 5

- 5 = 5 i

- - 5 = - 5 i

m = 5 i, m = - 5 i

(x + 6)^{2} = - 49

\frac{m ^{2}}{484} = \frac{1}{2}

- x^{3} + x^{2} + x - 1

- 9 + 4 (1.5 x - 2.5) - 7 x = - 7.25

x \cdot 0.08542 + (1 - x) \cdot 0.01192 = 0.0818

What are the solutions to the equation m^2+5=0 ?
The solutions to the equation m^2+5=0 are m=sqrt(5)i,m=-sqrt(5)i
Find the zeros of m^2+5=0
The zeros of m^2+5=0 are m=sqrt(5)i,m=-sqrt(5)i