What is factor (3x+1)^2-(x-4)^2 ?

The solution to factor (3x+1)^2-(x-4)^2 is (4x-3)(2x+5)

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factor (3x+1)^2-(x-4)^2

factor

(3 x + 1)^{2} - (x - 4)^{2}

(4 x - 3) (2 x + 5)

Solution steps

(3 x + 1)^{2} - (x - 4)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(3 x + 1)^{2} - (x - 4)^{2} = ((3 x + 1) + (x - 4)) ((3 x + 1) - (x - 4))

= ((3 x + 1) + (x - 4)) ((3 x + 1) - (x - 4))

Simplify

((3 x + 1) + (x - 4)) ((3 x + 1) - (x - 4)) : (4 x - 3) (2 x + 5)

= (4 x - 3) (2 x + 5)

2 x^{2} - 8 x - 42

9 ∣ x - 1 ∣ = - 45

24 (x - 1) = - 6 (4 - x) + 18 x

\frac{2 7 ^{2}}{2 7 ^{\frac{4}{3}}}

What is factor (3x+1)^2-(x-4)^2 ?
The solution to factor (3x+1)^2-(x-4)^2 is (4x-3)(2x+5)