What are the solutions to the equation 2w^2-3w-90=0 ?

The solutions to the equation 2w^2-3w-90=0 are w= 15/2 ,w=-6

Find the zeros of 2w^2-3w-90=0

The zeros of 2w^2-3w-90=0 are w= 15/2 ,w=-6

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2 w^{2} - 3 w - 90 = 0

w = \frac{15}{2}, w = - 6

Solution steps

2 w^{2} - 3 w - 90 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 90 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 90) = 27

w_{1, 2} = \frac{- ( - 3 ) \pm 27}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 27}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 27}{2 \cdot 2}

w = \frac{- ( - 3 ) + 27}{2 \cdot 2} : \frac{15}{2}

w = \frac{- ( - 3 ) - 27}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

w = \frac{15}{2}, w = - 6

- \frac{5}{2} (2)

x^{2} - 4 x - 21 = 0

1 4^{2} + 1 6^{2}

\frac{1}{2} + \frac{- 1}{2}

k + 6 \geq 19

What are the solutions to the equation 2w^2-3w-90=0 ?
The solutions to the equation 2w^2-3w-90=0 are w= 15/2 ,w=-6
Find the zeros of 2w^2-3w-90=0
The zeros of 2w^2-3w-90=0 are w= 15/2 ,w=-6