What are the solutions to the equation 2m^2-7m=-7m+49+m^2 ?

The solutions to the equation 2m^2-7m=-7m+49+m^2 are m=7,m=-7

Find the zeros of 2m^2-7m=-7m+49+m^2

The zeros of 2m^2-7m=-7m+49+m^2 are m=7,m=-7

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2 m^{2} - 7 m = - 7 m + 49 + m^{2}

m = 7, m = - 7

Solution steps

2 m^{2} - 7 m = - 7 m + 49 + m^{2}

Move

m^{2}

to the left side

m^{2} - 7 m = - 7 m + 49

Move

7 m

to the left side

m^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 49, m = - 49

49 = 7

- 49 = - 7

m = 7, m = - 7

2 x - 5 < - 11 or 5 x + 1 \geq 6

5 x^{2} = 14 x + 3

- 10 x < 80

\frac{13}{9} x + x = 88

x (x - 15) = 1 0^{2}

What are the solutions to the equation 2m^2-7m=-7m+49+m^2 ?
The solutions to the equation 2m^2-7m=-7m+49+m^2 are m=7,m=-7
Find the zeros of 2m^2-7m=-7m+49+m^2
The zeros of 2m^2-7m=-7m+49+m^2 are m=7,m=-7