What are the solutions to the equation z^2-6z+9=-4 ?

The solutions to the equation z^2-6z+9=-4 are z=3+2i,z=3-2i

Find the zeros of z^2-6z+9=-4

The zeros of z^2-6z+9=-4 are z=3+2i,z=3-2i

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z^{2} - 6 z + 9 = - 4

z = 3 + 2 i, z = 3 - 2 i

Solution steps

z^{2} - 6 z + 9 = - 4

Move

4

to the left side

z^{2} - 6 z + 13 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

z_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, z_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

z = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

z = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

z = 3 + 2 i, z = 3 - 2 i

- 4 x^{2} + 36

x^{3} - x^{2} + x + 3

\frac{2}{7} (\frac{665}{666}) + \frac{1}{9} = \frac{12}{5} (\frac{668}{666}) - \frac{14}{7}

3 x^{2} - 7 x + 2

\frac{4}{5 - 3 x} \leq - 1

What are the solutions to the equation z^2-6z+9=-4 ?
The solutions to the equation z^2-6z+9=-4 are z=3+2i,z=3-2i
Find the zeros of z^2-6z+9=-4
The zeros of z^2-6z+9=-4 are z=3+2i,z=3-2i