What are the solutions to the equation 4x^2-3x-8=0 ?

The solutions to the equation 4x^2-3x-8=0 are x=(3+sqrt(137))/8 ,x=(3-sqrt(137))/8

Find the zeros of 4x^2-3x-8=0

The zeros of 4x^2-3x-8=0 are x=(3+sqrt(137))/8 ,x=(3-sqrt(137))/8

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4 x^{2} - 3 x - 8 = 0

x = \frac{3 + 137}{8}, x = \frac{3 - 137}{8}

Solution steps

4 x^{2} - 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 ( - 8 )}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 (- 8) = 137

x_{1, 2} = \frac{- ( - 3 ) \pm 137}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 137}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 137}{2 \cdot 4}

x = \frac{- ( - 3 ) + 137}{2 \cdot 4} : \frac{3 + 137}{8}

x = \frac{- ( - 3 ) - 137}{2 \cdot 4} : \frac{3 - 137}{8}

The solutions to the quadratic equation are:

x = \frac{3 + 137}{8}, x = \frac{3 - 137}{8}

16 w^{2} + 24 w + 9

64 - x = 80 - 3 x

3 (3 + 2 i) - 2 (- 2 - 5 i)

16 d^{3} f - 64 d^{2} f + 48 df

\frac{1}{\frac{1}{2} + \frac{1}{5}}

What are the solutions to the equation 4x^2-3x-8=0 ?
The solutions to the equation 4x^2-3x-8=0 are x=(3+sqrt(137))/8 ,x=(3-sqrt(137))/8
Find the zeros of 4x^2-3x-8=0
The zeros of 4x^2-3x-8=0 are x=(3+sqrt(137))/8 ,x=(3-sqrt(137))/8