What are the solutions to the equation (x-2)^2-5=2x-6 ?

The solutions to the equation (x-2)^2-5=2x-6 are x=5,x=1

Find the zeros of (x-2)^2-5=2x-6

The zeros of (x-2)^2-5=2x-6 are x=5,x=1

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(x - 2)^{2} - 5 = 2 x - 6

x = 5, x = 1

Solution steps

(x - 2)^{2} - 5 = 2 x - 6

Expand

(x - 2)^{2} - 5 : x^{2} - 4 x - 1

x^{2} - 4 x - 1 = 2 x - 6

Move

6

to the left side

x^{2} - 4 x + 5 = 2 x

Move

2 x

to the left side

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

3 g + 24 = - 18

(2 x + 2) (5 x - 5) = 0

\frac{- 1}{- 5}

0.082 < 0.1

∣ x + 6 ∣ \geq 3

What are the solutions to the equation (x-2)^2-5=2x-6 ?
The solutions to the equation (x-2)^2-5=2x-6 are x=5,x=1
Find the zeros of (x-2)^2-5=2x-6
The zeros of (x-2)^2-5=2x-6 are x=5,x=1