What are the solutions to the equation x^2-14x+25=0 ?

The solutions to the equation x^2-14x+25=0 are x=7+2sqrt(6),x=7-2sqrt(6)

Find the zeros of x^2-14x+25=0

The zeros of x^2-14x+25=0 are x=7+2sqrt(6),x=7-2sqrt(6)

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x^{2} - 14 x + 25 = 0

x = 7 + 26, x = 7 - 26

Decimal Notation

x = 11.89897 \dots, x = 2.10102 \dots

Solution steps

x^{2} - 14 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 25 = 46

x_{1, 2} = \frac{- ( - 14 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 14 ) + 4 6}{2 \cdot 1} : 7 + 26

x = \frac{- ( - 14 ) - 4 6}{2 \cdot 1} : 7 - 26

The solutions to the quadratic equation are:

x = 7 + 26, x = 7 - 26

(2 k - 1)^{2} = 9

x (x - 3) + 2 \leq x + 2

2 a + 1 = a + 4

ln (e^{- 3})

\frac{3 π}{4} \cdot 2

What are the solutions to the equation x^2-14x+25=0 ?
The solutions to the equation x^2-14x+25=0 are x=7+2sqrt(6),x=7-2sqrt(6)
Find the zeros of x^2-14x+25=0
The zeros of x^2-14x+25=0 are x=7+2sqrt(6),x=7-2sqrt(6)