What are the solutions to the equation 5x^2-5=0 ?

The solutions to the equation 5x^2-5=0 are x=1,x=-1

Find the zeros of 5x^2-5=0

The zeros of 5x^2-5=0 are x=1,x=-1

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5 x^{2} - 5 = 0

x = 1, x = - 1

Solution steps

5 x^{2} - 5 = 0

Move

5

to the right side

5 x^{2} = 5

Divide both sides by

5

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

3 x^{2} + 5 x + 3 = 0

6 (\frac{3 x}{2} + 4) - 10 = \frac{1}{2} (4 x + 16)

24 x^{2} y - 72 x y

(t^{2})^{- 2} (t^{2})^{- 5}

9 x - 4 = 1

What are the solutions to the equation 5x^2-5=0 ?
The solutions to the equation 5x^2-5=0 are x=1,x=-1
Find the zeros of 5x^2-5=0
The zeros of 5x^2-5=0 are x=1,x=-1