What are the solutions to the equation 25x^2-95x-20=0 ?

The solutions to the equation 25x^2-95x-20=0 are x=4,x=-1/5

Find the zeros of 25x^2-95x-20=0

The zeros of 25x^2-95x-20=0 are x=4,x=-1/5

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25 x^{2} - 95 x - 20 = 0

x = 4, x = - \frac{1}{5}

Decimal Notation

x = 4, x = - 0.2

Solution steps

25 x^{2} - 95 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 95 ) \pm ( - 95 ) ^{2} - 4 \cdot 25 ( - 20 )}{2 \cdot 25}

(- 95)^{2} - 4 \cdot 25 (- 20) = 105

x_{1, 2} = \frac{- ( - 95 ) \pm 105}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 95 ) + 105}{2 \cdot 25}, x_{2} = \frac{- ( - 95 ) - 105}{2 \cdot 25}

x = \frac{- ( - 95 ) + 105}{2 \cdot 25} : 4

x = \frac{- ( - 95 ) - 105}{2 \cdot 25} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 4, x = - \frac{1}{5}

x^{2} + 11 x + 28 \geq 0

3 (x - 2) + 9 = 0

\frac{x - 1}{x + 3} > \frac{x - 4}{x + 2}

4 - \frac{8}{3}

2 y^{2} = 18

What are the solutions to the equation 25x^2-95x-20=0 ?
The solutions to the equation 25x^2-95x-20=0 are x=4,x=-1/5
Find the zeros of 25x^2-95x-20=0
The zeros of 25x^2-95x-20=0 are x=4,x=-1/5