What is |2x-7|+x>= 6 ?

The solution to |2x-7|+x>= 6 is x = 13/3

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|2x-7|+x>= 6

∣ 2 x - 7 ∣ + x \geq 6

x \leq 1 or x \geq \frac{13}{3}

Interval Notation

(- \infty, 1] \cup [\frac{13}{3}, \infty)

Decimal Notation

x \leq 1 or x \geq 4.33333 \dots

Solution steps

∣ 2 x - 7 ∣ + x \geq 6

Find positive and negative intervals

x < \frac{7}{2}, x \geq \frac{7}{2}

Solve the inequality for each interval

x \leq 1 or x \geq \frac{13}{3}

- x^{3} + 3 x^{2} - 4

- 2 x + 4 x + 3

(\frac{1}{5})^{5}

\frac{3 ( j ^{5} ) ^{4}}{4 j ^{2}}

\frac{5 - 2 x}{5} + \frac{x - 4}{10} = \frac{9}{10}