What are the solutions to the equation 15x^2+2x-10=0 ?

The solutions to the equation 15x^2+2x-10=0 are x=(-1+sqrt(151))/(15),x=-(1+sqrt(151))/(15)

Find the zeros of 15x^2+2x-10=0

The zeros of 15x^2+2x-10=0 are x=(-1+sqrt(151))/(15),x=-(1+sqrt(151))/(15)

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15 x^{2} + 2 x - 10 = 0

x = \frac{- 1 + 151}{15}, x = - \frac{1 + 151}{15}

Decimal Notation

x = 0.75254 \dots, x = - 0.88588 \dots

Solution steps

15 x^{2} + 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 15 ( - 10 )}{2 \cdot 15}

2^{2} - 4 \cdot 15 (- 10) = 2151

x_{1, 2} = \frac{- 2 \pm 2 151}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 2 + 2 151}{2 \cdot 15}, x_{2} = \frac{- 2 - 2 151}{2 \cdot 15}

x = \frac{- 2 + 2 151}{2 \cdot 15} : \frac{- 1 + 151}{15}

x = \frac{- 2 - 2 151}{2 \cdot 15} : - \frac{1 + 151}{15}

The solutions to the quadratic equation are:

x = \frac{- 1 + 151}{15}, x = - \frac{1 + 151}{15}

3 x^{2} - 2 x - 1 = 0

\frac{1}{12} + \frac{5}{6}

(27 x^{6})^{\frac{2}{3}}

8 = \frac{3}{4} (5 x + 20)

\frac{1}{x ^{2} - 1} + 3 \geq 0

What are the solutions to the equation 15x^2+2x-10=0 ?
The solutions to the equation 15x^2+2x-10=0 are x=(-1+sqrt(151))/(15),x=-(1+sqrt(151))/(15)
Find the zeros of 15x^2+2x-10=0
The zeros of 15x^2+2x-10=0 are x=(-1+sqrt(151))/(15),x=-(1+sqrt(151))/(15)