What are the solutions to the equation 4x^2-11x+7=0 ?

The solutions to the equation 4x^2-11x+7=0 are x= 7/4 ,x=1

Find the zeros of 4x^2-11x+7=0

The zeros of 4x^2-11x+7=0 are x= 7/4 ,x=1

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4 x^{2} - 11 x + 7 = 0

x = \frac{7}{4}, x = 1

Decimal Notation

x = 1.75, x = 1

Solution steps

4 x^{2} - 11 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 4 \cdot 7}{2 \cdot 4}

(- 11)^{2} - 4 \cdot 4 \cdot 7 = 3

x_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 4}, x_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 4}

x = \frac{- ( - 11 ) + 3}{2 \cdot 4} : \frac{7}{4}

x = \frac{- ( - 11 ) - 3}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = 1

2 x^{3} + 2 x^{2} - 4 x

\frac{3}{9} \cdot \frac{2}{8}

17 + k \leq 10

400 = - 2 [1 - 8 x]

x = - 3 (x + 7) (x - 2)

What are the solutions to the equation 4x^2-11x+7=0 ?
The solutions to the equation 4x^2-11x+7=0 are x= 7/4 ,x=1
Find the zeros of 4x^2-11x+7=0
The zeros of 4x^2-11x+7=0 are x= 7/4 ,x=1