What are the solutions to the equation 3x^2+14x-40=0 ?

The solutions to the equation 3x^2+14x-40=0 are x=2,x=-20/3

Find the zeros of 3x^2+14x-40=0

The zeros of 3x^2+14x-40=0 are x=2,x=-20/3

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3 x^{2} + 14 x - 40 = 0

x = 2, x = - \frac{20}{3}

Decimal Notation

x = 2, x = - 6.66666 \dots

Solution steps

3 x^{2} + 14 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 ( - 40 )}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 (- 40) = 26

x_{1, 2} = \frac{- 14 \pm 26}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 26}{2 \cdot 3}, x_{2} = \frac{- 14 - 26}{2 \cdot 3}

x = \frac{- 14 + 26}{2 \cdot 3} : 2

x = \frac{- 14 - 26}{2 \cdot 3} : - \frac{20}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{20}{3}

(\frac{3}{2})^{3}

a^{2} - 4 a - 24 + 6 a

17 x - x^{2} = 52

\frac{4}{6} + \frac{4}{8}

(2 x + 5)^{2} = 49

What are the solutions to the equation 3x^2+14x-40=0 ?
The solutions to the equation 3x^2+14x-40=0 are x=2,x=-20/3
Find the zeros of 3x^2+14x-40=0
The zeros of 3x^2+14x-40=0 are x=2,x=-20/3