What is 2/(2x-1)> 3/(3x-4) ?

The solution to 2/(2x-1)> 3/(3x-4) is 1/2 <x< 4/3

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2/(2x-1)> 3/(3x-4)

\frac{2}{2 x - 1} > \frac{3}{3 x - 4}

\frac{1}{2} < x < \frac{4}{3}

Interval Notation

(\frac{1}{2}, \frac{4}{3})

Decimal Notation

0.5 < x < 1.33333 \dots

Solution steps

\frac{2}{2 x - 1} > \frac{3}{3 x - 4}

Rewrite in standard form

\frac{1}{( 2 x - 1 ) ( 3 x - 4 )} < 0

\frac{1}{a} < 0

then

a < 0

(2 x - 1) (3 x - 4) < 0

Identify the intervals

\frac{1}{2} < x < \frac{4}{3}

(- 3 + i)^{2}

2 (4 x + 3) - 9 = 45

(\frac{1}{6} a^{5}) (- 3 a^{2}) (4 a^{7})

2 x - \frac{π}{3} = 2 π

4 - (u + 3) \leq 3 (3 - u)