What are the solutions to the equation -x^2-6x+6=0 ?

The solutions to the equation -x^2-6x+6=0 are x=-3-sqrt(15),x=sqrt(15)-3

Find the zeros of -x^2-6x+6=0

The zeros of -x^2-6x+6=0 are x=-3-sqrt(15),x=sqrt(15)-3

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- x^{2} - 6 x + 6 = 0

x = - 3 - 15, x = 15 - 3

Decimal Notation

x = - 6.87298 \dots, x = 0.87298 \dots

Solution steps

- x^{2} - 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 6 = 215

x_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 15}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 15}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 15}{2 ( - 1 )} : - 3 - 15

x = \frac{- ( - 6 ) - 2 15}{2 ( - 1 )} : 15 - 3

The solutions to the quadratic equation are:

x = - 3 - 15, x = 15 - 3

x^{4} + 7 x^{2} - 144

\frac{( 4 - i )}{( 3 + 4 i )}

3 (x + 1) 2 = 108

\frac{3}{2 2} + \frac{5 2}{4}

25 m p^{2} - 45 m p

What are the solutions to the equation -x^2-6x+6=0 ?
The solutions to the equation -x^2-6x+6=0 are x=-3-sqrt(15),x=sqrt(15)-3
Find the zeros of -x^2-6x+6=0
The zeros of -x^2-6x+6=0 are x=-3-sqrt(15),x=sqrt(15)-3