en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5|8-x|+7<= 42

Solution

5 ∣ 8 - x ∣ + 7 \leq 42

Solution

1 \leq x \leq 15

+1

Interval Notation

[1, 15]

Solution steps

5 ∣ 8 - x ∣ + 7 \leq 42

Move

7

to the right side

5 ∣ 8 - x ∣ \leq 35

Divide both sides by

5

∣ 8 - x ∣ \leq 7

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 7 \leq 8 - x \leq 7

8 - x \geq - 7 and 8 - x \leq 7

x \leq 15 and x \geq 1

Merge Overlapping Intervals

1 \leq x \leq 15

Popular Examples

∣ x - 2 ∣ < 1

x^{2} + 6 x = 0

6x-8x^2-((x-2))/5 = 1/2 x+3/2-((x-1))/4

6 x - 8 x^{2} - \frac{( x - 2 )}{5} = \frac{1}{2} x + \frac{3}{2} - \frac{( x - 1 )}{4}

4 x + 3 = 2 (5 + 2 x)

∣ 4 - 5 x ∣ \leq 19

Frequently Asked Questions (FAQ)

What is 5|8-x|+7<= 42 ?
The solution to 5|8-x|+7<= 42 is 1<= x<= 15