What are the solutions to the equation 2x^2+5=9 ?

The solutions to the equation 2x^2+5=9 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 2x^2+5=9

The zeros of 2x^2+5=9 are x=sqrt(2),x=-sqrt(2)

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2 x^{2} + 5 = 9

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

2 x^{2} + 5 = 9

Move

5

to the right side

2 x^{2} = 4

Divide both sides by

2

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

3 x + 12 > 3

0. 3^{4}

\frac{7}{3 x ^{2} y} + \frac{9}{6 x y ^{2}}

x^{2} - 10 = - 3 x

(x - 5)^{2} (x + 1) < 0

What are the solutions to the equation 2x^2+5=9 ?
The solutions to the equation 2x^2+5=9 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 2x^2+5=9
The zeros of 2x^2+5=9 are x=sqrt(2),x=-sqrt(2)