What are the solutions to the equation (x^2)/6-x/3 =1 ?

The solutions to the equation (x^2)/6-x/3 =1 are x=1+sqrt(7),x=1-sqrt(7)

Find the zeros of (x^2)/6-x/3 =1

The zeros of (x^2)/6-x/3 =1 are x=1+sqrt(7),x=1-sqrt(7)

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\frac{x ^{2}}{6} - \frac{x}{3} = 1

x = 1 + 7, x = 1 - 7

Decimal Notation

x = 3.64575 \dots, x = - 1.64575 \dots

Solution steps

\frac{x ^{2}}{6} - \frac{x}{3} = 1

Find Least Common Multiplier of

6, 3 : 6

Multiply by LCM=

6

\frac{x ^{2}}{6} \cdot 6 - \frac{x}{3} \cdot 6 = 1 \cdot 6

Simplify

x^{2} - 2 x = 6

Move

6

to the left side

x^{2} - 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 6) = 27

x_{1, 2} = \frac{- ( - 2 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 7}{2 \cdot 1} : 1 + 7

x = \frac{- ( - 2 ) - 2 7}{2 \cdot 1} : 1 - 7

The solutions to the quadratic equation are:

x = 1 + 7, x = 1 - 7

3 x^{2} + 7 x = 0

\frac{5 x ^{4} - 46 x ^{3} + 84 x ^{2} - 50 x + 7}{x - 1}

- 42 \cdot 47

5 s + 2 > 7

\frac{\frac{1}{2}}{\frac{2}{3}}

What are the solutions to the equation (x^2)/6-x/3 =1 ?
The solutions to the equation (x^2)/6-x/3 =1 are x=1+sqrt(7),x=1-sqrt(7)
Find the zeros of (x^2)/6-x/3 =1
The zeros of (x^2)/6-x/3 =1 are x=1+sqrt(7),x=1-sqrt(7)