What are the solutions to the equation x^2+6x+9=20 ?

The solutions to the equation x^2+6x+9=20 are x=-3+2sqrt(5),x=-3-2sqrt(5)

Find the zeros of x^2+6x+9=20

The zeros of x^2+6x+9=20 are x=-3+2sqrt(5),x=-3-2sqrt(5)

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x^{2} + 6 x + 9 = 20

x = - 3 + 25, x = - 3 - 25

Decimal Notation

x = 1.47213 \dots, x = - 7.47213 \dots

Solution steps

x^{2} + 6 x + 9 = 20

Move

20

to the left side

x^{2} + 6 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 11) = 45

x_{1, 2} = \frac{- 6 \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 5}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 5}{2 \cdot 1}

x = \frac{- 6 + 4 5}{2 \cdot 1} : - 3 + 25

x = \frac{- 6 - 4 5}{2 \cdot 1} : - 3 - 25

The solutions to the quadratic equation are:

x = - 3 + 25, x = - 3 - 25

\frac{- 3}{- 1}

- 16 t^{2} + 128 t + 1680 = 0

∣ x + 6 ∣ = 2

x^{2} + (x + 7)^{2} = 1 3^{2}

- ∣ 2 x + 4 ∣ = - 6

What are the solutions to the equation x^2+6x+9=20 ?
The solutions to the equation x^2+6x+9=20 are x=-3+2sqrt(5),x=-3-2sqrt(5)
Find the zeros of x^2+6x+9=20
The zeros of x^2+6x+9=20 are x=-3+2sqrt(5),x=-3-2sqrt(5)