What are the solutions to the equation 3x^2=6x+2 ?

The solutions to the equation 3x^2=6x+2 are x=(3+sqrt(15))/3 ,x=(3-sqrt(15))/3

Find the zeros of 3x^2=6x+2

The zeros of 3x^2=6x+2 are x=(3+sqrt(15))/3 ,x=(3-sqrt(15))/3

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3 x^{2} = 6 x + 2

x = \frac{3 + 15}{3}, x = \frac{3 - 15}{3}

Decimal Notation

x = 2.29099 \dots, x = - 0.29099 \dots

Solution steps

3 x^{2} = 6 x + 2

Move

2

to the left side

3 x^{2} - 2 = 6 x

Move

6 x

to the left side

3 x^{2} - 2 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 2) = 215

x_{1, 2} = \frac{- ( - 6 ) \pm 2 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 15}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 15}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 15}{2 \cdot 3} : \frac{3 + 15}{3}

x = \frac{- ( - 6 ) - 2 15}{2 \cdot 3} : \frac{3 - 15}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 15}{3}, x = \frac{3 - 15}{3}

y, x^{2} + 2 y^{2} = 0

9 w^{2} - 48 w v + 64 v^{2}

\frac{2}{3} + \frac{1}{2} - \frac{1}{3}

2 (- 2)^{3} + 3 (- 2)^{2} - 12 (- 2) + 6

\frac{1}{2} - \frac{m}{8} < \frac{7}{8}

What are the solutions to the equation 3x^2=6x+2 ?
The solutions to the equation 3x^2=6x+2 are x=(3+sqrt(15))/3 ,x=(3-sqrt(15))/3
Find the zeros of 3x^2=6x+2
The zeros of 3x^2=6x+2 are x=(3+sqrt(15))/3 ,x=(3-sqrt(15))/3