What are the solutions to the equation 3x^2+15x-5=0 ?

The solutions to the equation 3x^2+15x-5=0 are x=(-15+sqrt(285))/6 ,x=(-15-sqrt(285))/6

Find the zeros of 3x^2+15x-5=0

The zeros of 3x^2+15x-5=0 are x=(-15+sqrt(285))/6 ,x=(-15-sqrt(285))/6

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3 x^{2} + 15 x - 5 = 0

x = \frac{- 15 + 285}{6}, x = \frac{- 15 - 285}{6}

Decimal Notation

x = 0.31365 \dots, x = - 5.31365 \dots

Solution steps

3 x^{2} + 15 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 (- 5) = 285

x_{1, 2} = \frac{- 15 \pm 285}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 15 + 285}{2 \cdot 3}, x_{2} = \frac{- 15 - 285}{2 \cdot 3}

x = \frac{- 15 + 285}{2 \cdot 3} : \frac{- 15 + 285}{6}

x = \frac{- 15 - 285}{2 \cdot 3} : \frac{- 15 - 285}{6}

The solutions to the quadratic equation are:

x = \frac{- 15 + 285}{6}, x = \frac{- 15 - 285}{6}

\frac{2 + i}{4 - 3 i}

5 t^{2} - 24 t - 5

- 8 \leq 5 x - 9 \leq 5

5 x^{2} y^{- 3}

\frac{1}{4} (8 - 4 p) + 2 p = 12

What are the solutions to the equation 3x^2+15x-5=0 ?
The solutions to the equation 3x^2+15x-5=0 are x=(-15+sqrt(285))/6 ,x=(-15-sqrt(285))/6
Find the zeros of 3x^2+15x-5=0
The zeros of 3x^2+15x-5=0 are x=(-15+sqrt(285))/6 ,x=(-15-sqrt(285))/6