What are the solutions to the equation -16t^2+100t+75=0 ?

The solutions to the equation -16t^2+100t+75=0 are t=-(5(sqrt(37)-5))/8 ,t=(5(5+sqrt(37)))/8

Find the zeros of -16t^2+100t+75=0

The zeros of -16t^2+100t+75=0 are t=-(5(sqrt(37)-5))/8 ,t=(5(5+sqrt(37)))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 t^{2} + 100 t + 75 = 0

t = - \frac{5 ( 37 - 5 )}{8}, t = \frac{5 ( 5 + 37 )}{8}

Decimal Notation

t = - 0.67672 \dots, t = 6.92672 \dots

Solution steps

- 16 t^{2} + 100 t + 75 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 16 ) \cdot 75}{2 ( - 16 )}

10 0^{2} - 4 (- 16) \cdot 75 = 2037

t_{1, 2} = \frac{- 100 \pm 20 37}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 100 + 20 37}{2 ( - 16 )}, t_{2} = \frac{- 100 - 20 37}{2 ( - 16 )}

t = \frac{- 100 + 20 37}{2 ( - 16 )} : - \frac{5 ( 37 - 5 )}{8}

t = \frac{- 100 - 20 37}{2 ( - 16 )} : \frac{5 ( 5 + 37 )}{8}

The solutions to the quadratic equation are:

t = - \frac{5 ( 37 - 5 )}{8}, t = \frac{5 ( 5 + 37 )}{8}

\frac{1 + \frac{3}{2}}{2}

a c x^{2} + a d x + b c x + b d

(- x)^{3}

4 x^{- 4} - 16 x^{- 2} + 4

125 0^{\frac{3}{4}}

What are the solutions to the equation -16t^2+100t+75=0 ?
The solutions to the equation -16t^2+100t+75=0 are t=-(5(sqrt(37)-5))/8 ,t=(5(5+sqrt(37)))/8
Find the zeros of -16t^2+100t+75=0
The zeros of -16t^2+100t+75=0 are t=-(5(sqrt(37)-5))/8 ,t=(5(5+sqrt(37)))/8