What are the solutions to the equation 4x^2-3=-4x ?

The solutions to the equation 4x^2-3=-4x are x= 1/2 ,x=-3/2

Find the zeros of 4x^2-3=-4x

The zeros of 4x^2-3=-4x are x= 1/2 ,x=-3/2

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4 x^{2} - 3 = - 4 x

x = \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = 0.5, x = - 1.5

Solution steps

4 x^{2} - 3 = - 4 x

Move

4 x

to the left side

4 x^{2} - 3 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- 4 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8}{2 \cdot 4}, x_{2} = \frac{- 4 - 8}{2 \cdot 4}

x = \frac{- 4 + 8}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 4 - 8}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{3}{2}

(81 x^{24} y^{- 20})^{\frac{1}{4}}

a^{2} - 3 a - 4

x^{2} - 8 x - 105 = - 10

\frac{3 x + 5}{3} = 9

\frac{n ^{2} - n - 12}{n ^{2} - 4 n}

What are the solutions to the equation 4x^2-3=-4x ?
The solutions to the equation 4x^2-3=-4x are x= 1/2 ,x=-3/2
Find the zeros of 4x^2-3=-4x
The zeros of 4x^2-3=-4x are x= 1/2 ,x=-3/2