What are the solutions to the equation x^2-18x+76=0 ?

The solutions to the equation x^2-18x+76=0 are x=9+sqrt(5),x=9-sqrt(5)

Find the zeros of x^2-18x+76=0

The zeros of x^2-18x+76=0 are x=9+sqrt(5),x=9-sqrt(5)

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x^{2} - 18 x + 76 = 0

x = 9 + 5, x = 9 - 5

Decimal Notation

x = 11.23606 \dots, x = 6.76393 \dots

Solution steps

x^{2} - 18 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 76}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 76 = 25

x_{1, 2} = \frac{- ( - 18 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 5}{2 \cdot 1} : 9 + 5

x = \frac{- ( - 18 ) - 2 5}{2 \cdot 1} : 9 - 5

The solutions to the quadratic equation are:

x = 9 + 5, x = 9 - 5

\frac{- 10 + 3 i}{2 i}

\frac{7}{5} + \frac{8}{15} + \frac{11}{60}

- 6 x^{2} - 25 x - 25

(\frac{1}{4})^{- 2}

m^{4} + 10 m^{2} + 25

What are the solutions to the equation x^2-18x+76=0 ?
The solutions to the equation x^2-18x+76=0 are x=9+sqrt(5),x=9-sqrt(5)
Find the zeros of x^2-18x+76=0
The zeros of x^2-18x+76=0 are x=9+sqrt(5),x=9-sqrt(5)