What are the solutions to the equation x^2+(3/5)^2=1 ?

The solutions to the equation x^2+(3/5)^2=1 are x= 4/5 ,x=-4/5

Find the zeros of x^2+(3/5)^2=1

The zeros of x^2+(3/5)^2=1 are x= 4/5 ,x=-4/5

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x^{2} + (\frac{3}{5})^{2} = 1

x = \frac{4}{5}, x = - \frac{4}{5}

Decimal Notation

x = 0.8, x = - 0.8

Solution steps

x^{2} + (\frac{3}{5})^{2} = 1

Expand

x^{2} + (\frac{3}{5})^{2} : x^{2} + \frac{9}{25}

x^{2} + \frac{9}{25} = 1

Move

\frac{9}{25}

to the right side

x^{2} = 1 - \frac{9}{25}

Simplify

1 - \frac{9}{25} : \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{25}, x = - \frac{16}{25}

\frac{16}{25} = \frac{4}{5}

- \frac{16}{25} = - \frac{4}{5}

x = \frac{4}{5}, x = - \frac{4}{5}

x + x^{2}

35 x^{2} + 63 x^{4}

1 - \frac{3}{8}

- 256

\frac{3 2}{3}

What are the solutions to the equation x^2+(3/5)^2=1 ?
The solutions to the equation x^2+(3/5)^2=1 are x= 4/5 ,x=-4/5
Find the zeros of x^2+(3/5)^2=1
The zeros of x^2+(3/5)^2=1 are x= 4/5 ,x=-4/5