What are the solutions to the equation -2x^2+4x-1=0 ?

The solutions to the equation -2x^2+4x-1=0 are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2

Find the zeros of -2x^2+4x-1=0

The zeros of -2x^2+4x-1=0 are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2

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- 2 x^{2} + 4 x - 1 = 0

x = \frac{2 - 2}{2}, x = \frac{2 + 2}{2}

Decimal Notation

x = 0.29289 \dots, x = 1.70710 \dots

Solution steps

- 2 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

4^{2} - 4 (- 2) (- 1) = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 ( - 2 )}, x_{2} = \frac{- 4 - 2 2}{2 ( - 2 )}

x = \frac{- 4 + 2 2}{2 ( - 2 )} : \frac{2 - 2}{2}

x = \frac{- 4 - 2 2}{2 ( - 2 )} : \frac{2 + 2}{2}

The solutions to the quadratic equation are:

x = \frac{2 - 2}{2}, x = \frac{2 + 2}{2}

6 x - 2 (x + 9) = 2

(5^{3} x^{2} y^{4})^{0}

4 x + 5 x = 5 x + 7

3 x^{2} + 7 = 6 x

\frac{2}{3} + \frac{1}{5} x - \frac{1}{4} = \frac{4}{5} x

What are the solutions to the equation -2x^2+4x-1=0 ?
The solutions to the equation -2x^2+4x-1=0 are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2
Find the zeros of -2x^2+4x-1=0
The zeros of -2x^2+4x-1=0 are x=(2-sqrt(2))/2 ,x=(2+sqrt(2))/2