What are the solutions to the equation 500=30(25-t^2) ?

The solutions to the equation 500=30(25-t^2) are t= 5/(sqrt(3)),t=-5/(sqrt(3))

Find the zeros of 500=30(25-t^2)

The zeros of 500=30(25-t^2) are t= 5/(sqrt(3)),t=-5/(sqrt(3))

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500 = 30 (25 - t^{2})

t = \frac{5}{3}, t = - \frac{5}{3}

Decimal Notation

t = 2.88675 \dots, t = - 2.88675 \dots

Solution steps

500 = 30 (25 - t^{2})

Switch sides

30 (25 - t^{2}) = 500

Divide both sides by

30

25 - t^{2} = \frac{50}{3}

Move

25

to the right side

- t^{2} = - \frac{25}{3}

Divide both sides by

- 1

t^{2} = \frac{25}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{25}{3}, t = - \frac{25}{3}

\frac{25}{3} = \frac{5}{3}

- \frac{25}{3} = - \frac{5}{3}

t = \frac{5}{3}, t = - \frac{5}{3}

- \frac{3}{6}

\frac{( i x + 1 + 6 i )}{i}

7 x^{2} - 6 x = 0

(- 2 x)^{3}

9 (x + 7) \geq 198

What are the solutions to the equation 500=30(25-t^2) ?
The solutions to the equation 500=30(25-t^2) are t= 5/(sqrt(3)),t=-5/(sqrt(3))
Find the zeros of 500=30(25-t^2)
The zeros of 500=30(25-t^2) are t= 5/(sqrt(3)),t=-5/(sqrt(3))