What is sqrt(3x+6)<= 3 ?

The solution to sqrt(3x+6)<= 3 is -2<= x<= 1

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sqrt(3x+6)<= 3

3 x + 6 \leq 3

- 2 \leq x \leq 1

Interval Notation

[- 2, 1]

Solution steps

3 x + 6 \leq 3

Square both sides

(3 x + 6)^{2} \leq 3^{2}

Simplify

3 x + 6 \leq 9

3 x + 6 \leq 9 : x \leq 1

x \leq 1

Find singularity points

Find non-negative values for radicals:

x \geq - 2

Combine the intervals

x \leq 1 and x \geq - 2

Merge Overlapping Intervals

- 2 \leq x \leq 1

4^{2} + 8^{2}

\frac{3}{\frac{1}{2}}

25 c^{2} - 16

3 x = - 15

136 = 3 x - 5 (6 x + 16)