What is the answer to (x-12)/4+x/2+(x+2x)/9 =0 ?

The answer to (x-12)/4+x/2+(x+2x)/9 =0 is x= 36/13

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(x-12)/4+x/2+(x+2x)/9 =0

\frac{x - 12}{4} + \frac{x}{2} + \frac{x + 2 x}{9} = 0

x = \frac{36}{13}

Decimal Notation

x = 2.76923 \dots

Solution steps

\frac{x - 12}{4} + \frac{x}{2} + \frac{x + 2 x}{9} = 0

\frac{x + 2 x}{9} = \frac{x}{3}

\frac{x - 12}{4} + \frac{x}{2} + \frac{x}{3} = 0

Multiply by LCM

3 (x - 12) + 10 x = 0

Expand

3 (x - 12) + 10 x : 13 x - 36

13 x - 36 = 0

Move

36

to the right side

13 x = 36

Divide both sides by

13

x = \frac{36}{13}

2 x^{3} - 5 x^{2} + x + 2

x^{\frac{5}{4}}

x - (2 x + 1) = 8 - (3 x + 3)

y^{2} - 5 y + 6 = 0

1 + 8 x - 14 = 19

What is the answer to (x-12)/4+x/2+(x+2x)/9 =0 ?
The answer to (x-12)/4+x/2+(x+2x)/9 =0 is x= 36/13
Solve for x: (x-12)/4+x/2+(x+2x)/9 =0
The solution is x= 36/13