What are the solutions to the equation y^2-26y+29=0 ?

The solutions to the equation y^2-26y+29=0 are y=13+2sqrt(35),y=13-2sqrt(35)

Find the zeros of y^2-26y+29=0

The zeros of y^2-26y+29=0 are y=13+2sqrt(35),y=13-2sqrt(35)

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y^{2} - 26 y + 29 = 0

y = 13 + 235, y = 13 - 235

Solution steps

y^{2} - 26 y + 29 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot 29 = 435

y_{1, 2} = \frac{- ( - 26 ) \pm 4 35}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 26 ) + 4 35}{2 \cdot 1}, y_{2} = \frac{- ( - 26 ) - 4 35}{2 \cdot 1}

y = \frac{- ( - 26 ) + 4 35}{2 \cdot 1} : 13 + 235

y = \frac{- ( - 26 ) - 4 35}{2 \cdot 1} : 13 - 235

The solutions to the quadratic equation are:

y = 13 + 235, y = 13 - 235

4 x^{4} - 5 x^{2} - 9

v + \frac{2}{5} = \frac{1}{6}

2 x^{2} + 3 x - 2 < 0

- 10 - 40

\frac{18.7938 3 ^{2}}{2 \cdot 9.8}

What are the solutions to the equation y^2-26y+29=0 ?
The solutions to the equation y^2-26y+29=0 are y=13+2sqrt(35),y=13-2sqrt(35)
Find the zeros of y^2-26y+29=0
The zeros of y^2-26y+29=0 are y=13+2sqrt(35),y=13-2sqrt(35)