What are the solutions to the equation 4x^2=7 ?

The solutions to the equation 4x^2=7 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

Find the zeros of 4x^2=7

The zeros of 4x^2=7 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

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4 x^{2} = 7

x = \frac{7}{2}, x = - \frac{7}{2}

Solution steps

4 x^{2} = 7

Divide both sides by

4

x^{2} = \frac{7}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{4}, x = - \frac{7}{4}

\frac{7}{4} = \frac{7}{2}

- \frac{7}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

x - 7 = - 2

5 + ∣ 4 x - 5 ∣ = 5

(x - 5) (x - 4) = (x - 5) (x - 4)

2 x - 3 + 3 x = - 28

x^{2} \geq 64

What are the solutions to the equation 4x^2=7 ?
The solutions to the equation 4x^2=7 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2
Find the zeros of 4x^2=7
The zeros of 4x^2=7 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2