What is |(2x+1)/(x+1)|<= x ?

The solution to |(2x+1)/(x+1)| = (1+sqrt(5))/2

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|(2x+1)/(x+1)|<= x

\frac{2 x + 1}{x + 1} \leq x

x \geq \frac{1 + 5}{2}

Solution steps

\frac{2 x + 1}{x + 1} \leq x

Find positive and negative intervals

x < - 1, - 1 \leq x < - \frac{1}{2}, x \geq - \frac{1}{2}

Solve the inequality for each interval

No Solution or x \geq \frac{1 + 5}{2}

Merge Overlapping Intervals

x \geq \frac{1 + 5}{2}

u^{2} - 8 u + 16

\frac{6 c ^{2} d - 14 c d ^{2} + 2 d ^{3}}{2}

4 w^{2} - 52 w - 120

x^{3} - 81 x \leq 0

2 x^{2} - 4 = - 22

What is |(2x+1)/(x+1)|<= x ?
The solution to |(2x+1)/(x+1)|<= x is x>= (1+sqrt(5))/2