What are the solutions to the equation 4x^2=6+6x ?

The solutions to the equation 4x^2=6+6x are x=(3+sqrt(33))/4 ,x=(3-sqrt(33))/4

Find the zeros of 4x^2=6+6x

The zeros of 4x^2=6+6x are x=(3+sqrt(33))/4 ,x=(3-sqrt(33))/4

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4 x^{2} = 6 + 6 x

x = \frac{3 + 33}{4}, x = \frac{3 - 33}{4}

Solution steps

4 x^{2} = 6 + 6 x

Move

6 x

to the left side

4 x^{2} - 6 x = 6

Move

6

to the left side

4 x^{2} - 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 6)^{2} - 4 \cdot 4 (- 6) = 233

x_{1, 2} = \frac{- ( - 6 ) \pm 2 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 33}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 33}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 33}{2 \cdot 4} : \frac{3 + 33}{4}

x = \frac{- ( - 6 ) - 2 33}{2 \cdot 4} : \frac{3 - 33}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 33}{4}, x = \frac{3 - 33}{4}

1 = 0

∣ x - 6 ∣ > - 7

- 40 y^{6} x^{2} + 4 y^{2} x - 40 y^{2}

2 - 2 x > x + 64

3 x + 10 = x^{2}

What are the solutions to the equation 4x^2=6+6x ?
The solutions to the equation 4x^2=6+6x are x=(3+sqrt(33))/4 ,x=(3-sqrt(33))/4
Find the zeros of 4x^2=6+6x
The zeros of 4x^2=6+6x are x=(3+sqrt(33))/4 ,x=(3-sqrt(33))/4