What are the solutions to the equation x^2+14x=-130 ?

The solutions to the equation x^2+14x=-130 are x=-7+9i,x=-7-9i

Find the zeros of x^2+14x=-130

The zeros of x^2+14x=-130 are x=-7+9i,x=-7-9i

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x^{2} + 14 x = - 130

x = - 7 + 9 i, x = - 7 - 9 i

Solution steps

x^{2} + 14 x = - 130

Move

130

to the left side

x^{2} + 14 x + 130 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 130}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 130 : 18 i

x_{1, 2} = \frac{- 14 \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 18 i}{2 \cdot 1}, x_{2} = \frac{- 14 - 18 i}{2 \cdot 1}

x = \frac{- 14 + 18 i}{2 \cdot 1} : - 7 + 9 i

x = \frac{- 14 - 18 i}{2 \cdot 1} : - 7 - 9 i

The solutions to the quadratic equation are:

x = - 7 + 9 i, x = - 7 - 9 i

75 - 19 x = 11 (x + 15)

∣ 2 x - 3 ∣ = \frac{1}{x} + 3

5 + 2 x = 2 x + 6

(3 a^{\frac{1}{2}} b^{\frac{1}{3}})^{2}

7 x + (- 2) = - 44

What are the solutions to the equation x^2+14x=-130 ?
The solutions to the equation x^2+14x=-130 are x=-7+9i,x=-7-9i
Find the zeros of x^2+14x=-130
The zeros of x^2+14x=-130 are x=-7+9i,x=-7-9i