What are the solutions to the equation 0=x^2-6x+13 ?

The solutions to the equation 0=x^2-6x+13 are x=3+2i,x=3-2i

Find the zeros of 0=x^2-6x+13

The zeros of 0=x^2-6x+13 are x=3+2i,x=3-2i

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0 = x^{2} - 6 x + 13

x = 3 + 2 i, x = 3 - 2 i

Solution steps

0 = x^{2} - 6 x + 13

Switch sides

x^{2} - 6 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

x_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

x = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

x = 3 + 2 i, x = 3 - 2 i

(1 + \frac{3 i}{n})^{2}

8 y^{3} - 2 y^{4}

- 4 (y - 6) \leq (- 9 + y) (- 2)

\frac{3}{4} (2 x + 1) = 1

\frac{2}{9 i}

What are the solutions to the equation 0=x^2-6x+13 ?
The solutions to the equation 0=x^2-6x+13 are x=3+2i,x=3-2i
Find the zeros of 0=x^2-6x+13
The zeros of 0=x^2-6x+13 are x=3+2i,x=3-2i